$date1 = date(’Y-m-d’);
$date2 = ‘2006-07-01′;
$days = (strtotime($date1) – strtotime($date2)) / (60 * 60 * 24);
echo “Number of days since ‘2006-07-01′: $days”;
$date1 = date(’Y-m-d’);
$date2 = ‘2006-07-01′;
$days = (strtotime($date1) – strtotime($date2)) / (60 * 60 * 24);
echo “Number of days since ‘2006-07-01′: $days”;
strtotime() funtion need parameter
Thank , it is work perfectly